Question

The time taken by a particle performing shm to pass from point a to b where its velocities are same is 2s. After another 2s it returns to



b. The ratio of distance ob to its amplitude

Answer 1

Hey dear,

● Answer-

OB/A = 1/√2

● Explaination-

[Refer to the figure]

Time period is -

T = 2×4

T = 8 s

To solve this,

OB = Asin(wt)

OB/A = sin(2πt/T)

OB/A = sin(2π×1/8)

OB/A = 1/√2

Therefore, ratio of distance OB to A is 1/√2 .

Hope this helps you...