Question

The time taken by a person to cover 150 km was 2 hours more than the time taken in the return
journey. If he returned at a speed of 10 km/hr more than the speed while going, find the speed per
hour in each direction.​

Answer 1

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Answer:

let speed of person while going be x km/h

and speed while returning be y km/h

Step-by-step explanation:

y=10+x (2nd situation).................(1st eq.)

(150/x)-(150/y)=2 (1st situation)

From (1st);

(150/x)-(150/x+10)=2

(150x+1500-150x)÷(x²+10x)=2

1500=2(x²+10x)

x²+10x-750=0

x=(-10±√100+3000)÷2

x=(-10±√3100)÷2

x = -5 + 5√31km/h or -5-5√31km/h

x = 22.83km/h or -52.83km/h(rejected)

y=32.83km/h