The total cost of painting the curved surface of a solid cone at the rate of Rs.5 per sq. m is Rs.19800. If the radius of the base of cone is 21m, find its total surface area.
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Answer:
It costs Rs.2200 to paint the inner curved surface of a cylindrical vessel 10m deep. If the cost of painting is at the rate of Rs.20 per m
2
. Find capacity of the vessel.
A
96.25 m
3
B
56.25 m
3
C
96.75 m
3
D
91.25 m
3
ANSWER
Total cost of point=2200Rs.
cost of point/m
2
=20Rs.
depth of vessel=10m
Inner curved surface area painted=
cost/m
2
totalcost
=
20
2200
=110m
2
Now, 2πrh=110m
2
2×
7
22
×r×10=110
r=
2×22×10
110×7
=1.75m
∴ radius of the base is 1.75m.
capacity of vessel=πr
2
h=
7
22
×1.75×1.75×10
=96.25m
3
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