Question

The total mass of 2 mole of electrons ( mass of fe 9.1x10^-28g)

Answer 1

mass of 1 electron = 9.1 × 10^-31

1 Mole = 6.023 × 10^23

so 2 mole of electron has mass = 2 × 6.023 × 10^23 × 9.1 × 10^-31 = 109.62 × 10^-7 kg

hope it helps

Answer 2

Answer:

Required total mass of 2 mole of electron is $10.96 \times {10}^{ - 7} \: kg$

Explanation:

Given,

1 electron mass of one electron is

$9.1 \times {10}^{ - 28} \: g = 9.1 \times {10}^{ - 31} kg$

Let mass of 1 mole electron be x kg.

We know, 1 mole is $6.022 \times {10}^{23}$ particles.

So we put $6.022 \times {10}^{23}$ in the equation instead.

So,

$x = \frac{9.11 \times {10}^{ - 31} }{1 \times 6.022 \times {10}^{23} } \\ = 5.48 \times {10}^{ - 7} \: kg$

Therefore mass of 1 mole electron is $5.48 \times {10}^{ - 7} \: kg$

By Unitary method,mass of 2 mole electron is

$(2 \times 5.48\times {10}^{ - 7} ) = 10.96 \times {10}^{ - 7} \: kg$

Know more about electron:

A negatively charged subatomic particle that can be either bound to an atom or free (not bound) is called electron.An electron bound to an atom is one of the three main types of particles in an atom, the other two being protons and neutrons. Together, electrons, protons and neutrons form the nucleus of an atom.

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