Question

the total number of electrons in 4.2 grams of N3 ion is ​

Answer 1

Answer:

1.6 ×Na

Explanation:

given weight = 4.2 gm

molecule wt of N3 = 42 gm

so, moles = given wt /molecular wt

=> n = 4.2/42 = 0.1 moles.

now change mole to molecules.. by Multiplying with avagadro number Na ( 6.022×10^23)

=> molecules = 0.1× Na

now according to question we need to calculate total number of electron that means. we need to calculate the electron number present in its valence shell...

so for N3 ion..

valence e =15 +1 =16 as.. one N atom has 5 electron in its valence shell so 3 N atoms will have 15 e. and +1 as in question it is given ion

so now no of electron = 0.1 × 16 ×Na

= 1.6 Na atoms..

hope this will help u understand.

Answer 2

Answer:

Explanation:

Nitrogen-Symbol-N -7(atomic number)

N³⁻ ion = 1s²2s²2p⁶

Total number of electrons =10

atomic mass of N=14

14g of N³⁻ ion contains 10NA electrons

where NA - Avagadro number

so, 1 g of N³⁻ ion =10NA/14

∴4.2g of N³⁻ ion =4.2x 10NA/14

=3NA

∴The total number of electrons in 4.2g of N3- ion 3NA

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