Math, asked by biswajitpany57, 11 months ago

THE TOTAL NUMBER OF STUDENTS IN SECTION A & B OF CLASS IS 72.THE RATIO OF NUMBER OF STUDENTS A & B IS 7:5.THE AVERAGE WEIGHT OF STUDENTS OF STUDENTS IN SECTION B IS 20% MORE THAN THAT OF THE STUDENTS IN SECTION A.IF THE AVERAGE WEIGHT OF ALL STUDENTS IN CLASS IS 52 KG.WHAT IS AVERAGE WEIGHT OF SECTION B.​

Answers

Answered by kumarrajeevsingh1110
0

OK I will try it just give me only 1 hr

Answered by slicergiza
0

The average weight in section B would be 57.6 kg

Step-by-step explanation:

Given,

Total students = 72,

Ratio of students from A and B = 7 : 5,

Let students in A = 7x, students in B = 5x,

Where, x is any positive real number,

total students = 7x + 5x = 12x

\implies 12x = 72

\implies x =\frac{72}{12}=6

Thus, students in A = 7(6) = 42,

Students in B = 5(6) = 30,

Now, consider y be the average weight of students in A,

So, the average weight in B = (100+20)% of y

= 120% of y

= 1.2y

Sum of weights in A and B = (42)y + (30)1.2y = 42y + 36y = 78y

Average weight = \frac{\text{Sum of weights}}{\text{Total students}}

=\frac{78y}{72}

According to the question,

\frac{78y}{72}=52

\frac{3y}{72}=2

\implies y = \frac{144}{3}=48

Hence, the average weight in B = 1.2(48) = 57.6 kg

#Learn more:

Find the average of 12 number if first 8 numbers average is 21 find the average of last 4 numbers

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