Question

the train is running at 20 m per second on a railway line with radius of curvature 40,000 meter the distance between two rail is 1.5 m for safe running of train the elevation of outer rail over the inner rail is

Answer 1

First, use tanФ=v²/rg to find the elevation angle:

Accordingly, tanФ=(20x20)/40000x10

tanФ = 1/10³

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Now, we know that tan is ratio of perpendicular and base. Here, the base is the distance between the two rails and the perpendicular the elevation of outer rail over the inner rail.

Hence, 1/10³= Elevation/Distance between two rails

1/10³=Elevation/1.5 ⇒ Elevation = 1.5 / 10³ meter

= 1.5 millimeter

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Hope this helps! :D

Answer 2

Hope it helps you

Using the formula and applying the concept will help you