Question

The two adjacent sides of a rectangle are 5x^2 - 3y^2 and x^2+2xy.find the perimeter.
The question is below also at no. 19.

Answer 1

Perimeter of rectangle ->2(L+B)
2(5x^2-3y^2+x^2+2xy)
2(4x^2-5x^3)
8x^2-10xy^3
So, The perimeter of rectangle is 8x^2-10xy^3.

Answer 2

Perimeter = 2 (L + B)

=2×(5x^2 - 3y^2 + x^2 + 2xy)

=2×(5x^2 + x^2 - 3y^2 + 2xy)

=2×(6x^2 - 3y^2 + 2xy)

=12x^2 - 6y^2 + 4xy