The two adjacent sides of a rectangle are 5x^2 - 3y^2 and x^2+2xy.find the perimeter.
The question is below also at no. 19.
Answers
Answered by
99
Perimeter of rectangle ->2(L+B)
2(5x^2-3y^2+x^2+2xy)
2(4x^2-5x^3)
8x^2-10xy^3
So, The perimeter of rectangle is 8x^2-10xy^3.
2(5x^2-3y^2+x^2+2xy)
2(4x^2-5x^3)
8x^2-10xy^3
So, The perimeter of rectangle is 8x^2-10xy^3.
ahans9332:
Wrong answer.and that 5 star is for your mistake in addition and subtraction
If my answer is wrong, solve by your mind. I done your question directly. Ask to anyone. This answer is perfect or right.
Answered by
175
Perimeter = 2 (L + B)
=2×(5x^2 - 3y^2 + x^2 + 2xy)
=2×(5x^2 + x^2 - 3y^2 + 2xy)
=2×(6x^2 - 3y^2 + 2xy)
=12x^2 - 6y^2 + 4xy
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