Question

the two digit number is such that the product of its digits is 21 if 36 is subtracted from the number the digits are interchanged find the numbers​

Answer 1

Answer:

The number is 73.

Hope it helped you. Mark me as the brainliest.

Step-by-step explanation:

Answer 2

Answer:

The number is 73

Step-by-step explanation:

Let the number be 10a + b (as it is a two digit number)

where a and b lie in 1 and 9

we know that ab = 21 and

10a + b - 36 = 10b + a

this implies 9a - 9b = 36

= 9(a - b) = 36

= a - b = 4

Now we can say that a = 7 and b = 3 but if you want to solve it,

${(a + b)}^{2} = {(a - b)}^{2} + 4ab$

${(a + b)}^{2} = {4}^{2} + 4 \times21 \\ {(a + b)}^{2} = 100 \\ a + b = 10 \\ by \: solving \: the \: two \: equations \: we \: get \: a = 7 \: and \: b = 3$