The two perfect dice twice together find the probability of obtaining of
A} total sum of 5
B} more than 10
C} prime numbes
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Well total number of possible outcomes in case of two dices are = 6*6 = 36.
A. Total number of possible event
(i) 1+4
(ii) 2+3
(iii) 3+2
(iv) 4+1 i.e 4
So, probability = (4/36) = 1/9
similarly for others.
A. Total number of possible event
(i) 1+4
(ii) 2+3
(iii) 3+2
(iv) 4+1 i.e 4
So, probability = (4/36) = 1/9
similarly for others.
Anonymous:
sample space mn ata h dono
36 mn
oh, i think you are right,
i have updated my answer
hmm
be lodi
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hii
hey priya
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