The two roots of an equation x^3-9x^2+14x+24=0 are in the ratio 3:2.find the roots
Answers
Answered by
1
let the roots be 3α, 2α, β of the equation
x³-9x²+14x+24=0
then 5α+β=9
6α²+5αβ=14
6α²β=-24
solving,
x = -6,-4,1
x³-9x²+14x+24=0
then 5α+β=9
6α²+5αβ=14
6α²β=-24
solving,
x = -6,-4,1
Similar questions
English,
8 months ago
Hindi,
8 months ago
Math,
8 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago
Math,
1 year ago