The two roots of an equation x^3-9x^2+14x+24=0 are in the ratio 3:2.find the roots
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let the roots be 3α, 2α, β of the equation
x³-9x²+14x+24=0
then 5α+β=9
6α²+5αβ=14
6α²β=-24
solving,
x = -6,-4,1
x³-9x²+14x+24=0
then 5α+β=9
6α²+5αβ=14
6α²β=-24
solving,
x = -6,-4,1
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