The two values of x that are roots of this equation 2x^2+7x+6=0
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we can write it as
2x^2+4x+3x+6=0
2x(x+2)+3(x+2)=0
2x+3=0 & x+2=0
so the two values of x are -3/2 and -2
Answered by
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Heya!!
The equation is :
2x^2 + 7x + 6 = 0
By splitting middle term method ,
=) 2x^2 + 4x + 3x + 6 = 0
=) 2x(x + 2) + 3(x + 2) = 0
=) (x + 2) (2x + 3) = 0
=) x + 2 = 0 or, =) 2x + 3 = 0
=) x = -2 or, =) x = - 3/2
Hence, the value of x is -2 or -3/2.
Hope it helps uh :)
The equation is :
2x^2 + 7x + 6 = 0
By splitting middle term method ,
=) 2x^2 + 4x + 3x + 6 = 0
=) 2x(x + 2) + 3(x + 2) = 0
=) (x + 2) (2x + 3) = 0
=) x + 2 = 0 or, =) 2x + 3 = 0
=) x = -2 or, =) x = - 3/2
Hence, the value of x is -2 or -3/2.
Hope it helps uh :)
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