The unit vector along (i+j)
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Unit vector along(i+j)is∣i+j∣(i+j)
∣i+j∣ is magnitude of(i+j)
we know,
i and j are perpendicular to each other
So, ∣i+j∣=i2+j2+2ijcos90o
1+1=2
hence, unit vector along (i+j)is√2(i+j)
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Answer:
i+j+k are the unit vector
they are perpendicular to each other
x+y+z
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