The units digit of a two-digit number is 3 and seven times the sum of the digits is the
number itself. Find the number.
Answers
Answered by
0
Answer:
the only number which satisfies the given condition is 63
Answered by
2
Answer:
Unit of two digit number is 3
Let the tens digit number be x
The Number will be 10x + 3
Sum of two digit number = x + 3
According to the question now :
➳ 7(x + 3) = 10x + 3
➳ 7x + 21 = 10x + 3
➳ 21 - 3 = 10x - 7x
➳ 18 = 3x
➳ x = 18/3
➳ x = 6
Therefore, the tens digit number is 6.
Hence,
The required number = 10x + 3 = 10(6) + 3 = 63.
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