Math, asked by Pritam7681, 6 months ago

the value of -3sec^2 63 degree + 3 tan^2 63 degree is

Answers

Answered by rakshitbeniwal2007
0

Answer:

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Step-by-step explanation:

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Answered by sahaana964
0

Answer:

-3

Step-by-step explanation:

-3sec^2(63)+ 3tan^2(63)= -3(1+tan^(63)) + 3tan^2(63)

= -3 - 3tan^2(63) + 3tan^2(63)

= -3

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