Question

the value of a machine depreciates at the rate of 10% per annum . it was purchased 3 years ago . if it's present value is ₹291600 , for how much was it purchased​

Answer 1

Answer:

• Amount = Rs. 2,91,600
• depreciation rate = 10%p/a
• time (n) = 3 years
• initial prize (p)=?

$a = p(1 - \frac{r}{100} ) ^{n }$

2,91,600= p (1- 10/100)^3

2,91,600= p (1-1/10)^3

2,91,600= p (10-1/10)^3

2,91,600= p (9/10)^3

2,91,600=p × 729/1000

p = 2,91,600×1000/729

p=Rs. 1,00,02,194.78

Step-by-step explanation:

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