Question

The value of Bohr radius for hydrogen atom is
a) 0.529 × 10⁻⁸ cm
b) 0.529 × 10⁻¹⁰ cm
c) 0.529 × 10⁻⁶ cm
d) 0.529 × 10⁻¹² cm

Answer 1

According to Bohr's theory,
mvr = nh/2π
v = nh/2πmr ------(1)

Also centripetal force = Electrostatic force
mv²/r = KZe²/r²
v² = KZe²/mr ------(2)

From equations (1) and (2),
n²h²/4π²m²r² = KZe²/mr
⇒r = n²h²/4π²KZe²m
Put K = 1 , π = 3.14 , Z = 1
e = 4.8 × 10⁻¹⁰ esu , m = 9.1 × 10⁻²⁸ g , n = 1 and h = 6.62 × 10⁻²⁷ erg.sec

You will get , r = 0.529 A° or 0.529 × 10⁻⁸ cm

Hence, (a) is correct

Answer 2

Answer:

a) 0.529 ×10^8

Explanation:

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