The value of C such that a,-3,b,5,c are in AP
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Here -3 -a = b- (-3)
a+b = -6......(1)
Now
b-(-3) = 5-b : b= 1
So from equ (1)
a = -6-1 = -7
Now
5- b = c -5
5 -1 = c-5
c= 9
So a= - 7
b = 1
C=9
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