Question

the value of CFSE for d3 metal ion configuration is (a) -0. 8 b-1. 2 c- -1. 2 d- -0. 6 bhai jladi btaao​

Answer 1

Value of CFSE for d3 in octahedral complexes is

• $\boxed{\sf{-1.2 \Delta_{0}}}$

CFSE is the acronym for Crystal Field Stabilization Energy , helps to calculate the stabilisation energies for various octahedral complexes.

Calculation:

Arrangement of Electrons in the split "d" orbitals in the octahedral complexes ;

$0 \Delta_{0} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \underline{ - }} \: \: \: \boxed{\underline{ - }} \: \: \: \: \: \: e_{g} \\ \\ 3 \times ( - \frac{ 2}{5}) \Delta_{0} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\underline{ \red{ \uparrow}}} \: \: \boxed{\underline{ \red{ \uparrow}}} \: \: \boxed{\underline{ \red{\uparrow}}} \: \: \: \: t_{2}g$

$\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}\underline{-}$

$\sf{ \therefore \: CFSE = 3 \times ( - \dfrac{2}{5} )\Delta_{0} }$

$\sf{ = > \: CFSE = - \dfrac{6}{5} \Delta_{0} }$

$\sf{ = > \: CFSE = - 1.2\Delta_{0} }$

So, final answer is:

$\boxed{ \large{ \sf{ \red{ \: CFSE = - 1.2\Delta_{0} }}}}$