Question

the value of ground state energy of the hydrogen atom is - 13.6 find the energy required to move an electron from the ground state of the first excited state of the atom and determine kinetic energy and orbital radius in first excited state of the atom

Answer 1

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Answer 2

The energy required to move an electron from the ground state to the first excited state = 10.2 eV

The kinetic energy of the atom = 3.4 eV

The orbital radius in first excited state of the atom = 2.12 Angstrom

• energy required  = (- 13.6/ 4) + 13.6 = 10.2 eV
• kinetic energy = (- total energy)

                                 = 3.4 eV

• orbital radius = n * n * r0

                              = 2 * 2 * 0.53 Angstrom

                              = 2.12 Angstrom