the value of k for which the equation x²+2 (k+1) x + k²=0 has equal roots is
1
‐1
‐1/2
none of these
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1
Answer:
B is the answer!!!
Step-by-step explanation:
let x and y are two roots of that equation
the value of k for which the equation x²+2 (k+1) x + k²=0 has equal roots is,it means
x+y=-b/a=-2(k+1)/1=-2(k+1)
xy=k^2/1=k^2
Accordind to question
xy=x+y
k^2=-2(k+1)
k^2+2k+1=0
k^2+k+k+1=0
k(k+1)+1(k+1)=0
k=-1
thaank you!!
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