Math, asked by simrankhaire11, 7 months ago

the value of k for which the quadratic equation x²-4x+k=0 has equal roots is:


Answers

Answered by prajapatiayush009
1

Answer:

K = 4

Step-by-step explanation:

by the discriminant formula

D = b^2 -4ac

when the root are equal then D is equal to 0

so , (-4)^2 - 4*1*k = 0

16- 4k = 0

k = 4

Answered by VinayGulati
0

Answer:

4

Step-by-step explanation:

If the equation has equal roots then

√b^2-4ac=0

√(-4)^2-4*1*k=0

√16-4k=0

squaring both sides

16-4k=0

16=4k

k=16/4=4

Similar questions