Question

The value of log 2power 32 +log 4power 64
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Answer 1

Answer:

8

Step-by-step explanation:

$log_{2}32 + log_{4}64\\= log_{2}2^{5} + log_{4}4^{3}\\(Using property: log_{a}b^{c} = c*log_{a}b)\\=5 log_{2}2 + 3 log_{4}4\\(log_{a}a = 1)\\= 5(1)+3(1)\\= 8$