Question

The value of log with the base 3/4 1.3bar

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Answer 1

✰ Hello

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➥ Ur answer :

$log_{ \frac{3}{4} }(1.33) = log_{ 0.75 }(1.33) \\ = log_{ 0.75}( {0.75}^{ - 1} ) = - 1 \times log_{0.75}(0.75) \\ = - 1$

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