Question

the value of maximum amplitude produce due to interference of two wave is given by

y1=4 sin wt and y2 3 cos wt

Answer 1

the maximum value of amplitude shd be 1 or 7

Answer 2

Given that,

Equation of first wave is

$y_{1}=4\sin\omega t$

Equation of second wave is

$y_{1}=3\cos\omega t$

We need to write the amplitude of both waves

Compare of both equation from the general equation  

The general equation of wave is,

$y=a\sin\omega t$

Then,

Amplitude of first wave,

$a_{1}=4$

Amplitude of second wave,

$a_{2}=3$

We need to calculate the resultant of the amplitude

Using formula of resultant of amplitude

$a=\sqrt{a_{1}^2+a_{2}^2}$

Put the value of a₁ and a₂

$a=\sqrt{4^2+3^2}$

$a=5\ m/s^2$

Hence, The value of maximum amplitude produce due to interference of two waves is 5 m/s².