Question

The value of p(t)=2+t+2t^2-t^3 when t=0 is

Answer 1

Answer- The above question is from the chapter 'Polynomials'.

Let's know about polynomials first.

Polynomial- It is an algebraic expression involving use of variables and constants.

p(x)- It is used to denote a polynomial. It is read is 'Polynomial in x'.

Polynomials can be classified on two basis:

1) Number of terms

E.g.- Polynomial with one term is called monomial.

Two terms- binomial

Three terms- trinomial

2) Power of variable

E.g.- Polynomial with degree 1 is called linear polynomial.

degree 2- quadratic polynomial

degree 3- cubic polynomial

degree 4- bi-quadratic polynomial

Given question: The value of p(t) =2 + t + 2t² - t³ when t = 0 is __ .

Solution: p(t) =2 + t + 2t² - t³

When t = 0,

p(0) = 2 + 0 + 2(0)² - 0³

p(0) = 2 + 0 + 0 - 0

p(0) = 2

∴ The value of p(t) =2 + t + 2t² - t³ when t = 0 is 2.

Answer 2

Concept Introduction:-

It may be in the form of a word, a symbol, or a figure that reflects the arithmetic value of a quantity.

Given Information:-

We have been given that $p(t)=2+t+2t^2-t^3$

To Find:-

We have to find that value of $p(t)=2+t+2t^2-t^3$ when $t=0$

Solution:-

According to the problem

By putting the value of t in

$p(t)=2+t+2t^2-t^3\\p(0)=2+0+2(0)^2-(0)^3\\=2$

Final Answer:-

The value of $p(t)=2+t+2t^2-t^3$ in the given problem is $2$.

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