The value of tan-1{cos[pi/3]-sin[pi/3]/cos[pi/3]+sin[pi/3]} is
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Answer:
π/12 + nπ
Step-by-step explanation:
tan-1{cos[pi/3]-sin[pi/3]/cos[pi/3]+sin[pi/3]}
= tan-1{cos60-sin60/cos 60+sin 60}
= tan-1{1/2-√3/2÷ 1/2+√3/2}
= tan-1{1-√3÷ 1+√3}
= tan-1{1-√3}²÷ -2
= tan-1{4-2√3}÷ -2
= tan-1{-2+√3}
= pi/12 + npi
= π/12 + nπ , n is a positive integer
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