Question

the value of tan square 60 degree + sin square 45 degree is​

Answer 1

Given : $tan^{2} 60$° + $sin^{2}45$°

To Find : the value of the given problem

Solution :

$tan^{2} 60$ + $sin^{2}45$

= $(\sqrt{3}) ^{2} +(\frac{1}{\sqrt{2} } )^{2}$ ( tan60° = $\sqrt{3}$ and sin45° = $\frac{1}{\sqrt{2} }$ )

= 3 + $\frac{1}{2}$

= $\frac{6 + 1}{2}$

= $\frac{7}{2}$ or 3.5 (Answer)

Answer 2

$\displaystyle \sf{ {tan}^{2} {60}^{ \circ} + {sin}^{2} {45}^{ \circ} = \frac{7}{2} }$

Given :

$\displaystyle \sf{ {tan}^{2} {60}^{ \circ} + {sin}^{2} {45}^{ \circ} }$

To find : The value

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ {tan}^{2} {60}^{ \circ} + {sin}^{2} {45}^{ \circ} }$

Step 2 of 2 :

Find the value of the expression

$\displaystyle \sf{ {tan}^{2} {60}^{ \circ} + {sin}^{2} {45}^{ \circ} }$

$\displaystyle \sf{ = {( \sqrt{3} )}^{2} + { \bigg(\frac{1}{ \sqrt{2} } \bigg) }^{2} }$

$\displaystyle \sf{ = 3 + \frac{1}{2} }$

$\displaystyle \sf{ = \frac{6 + 1}{2} }$

$\displaystyle \sf{ = \frac{7}{2} }$

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