Question

the value of x if 8^(2x)8^(-5)=8^(7)?

Answer 1

Let's solve your equation step-by-step.

(8^2x)(8^−5)=8^7

132768(8^2x)=2097152

Step 1: Divide both sides by 1/32768.

132768(8^2x)132768=2097152132768

8^2x=68719476736

Step 2: Solve Exponent.

8^2x=68719476736

log(8^2x)=log(68719476736)(Take log of both sides)

2x*(log(8))=log(68719476736)

2x=log(68719476736)log(8)

2x=12

2x2=122(Divide both sides by 2)

x=6

Answer 2

Answer:

The required value of x = 6

Step-by-step explanation:

The equation is given to be :

$8^{2x}\times 8^{-5}=8^7$

We need to find the value of x from this equation.

$\implies 8^{2x}\times 8^{-5}=8^7$

Now, The bases are same in the multiplication, so the power will get add up

$\implies 8^{2x-5}=8^7$

Now, since the bases are same so on comparing both the sides

We get,

⇒ 2x - 5 = 7

⇒ 2x = 7 + 5

⇒ 2x = 12

⇒ x = 6

Thus, The required value of x = 6