Question

the value of x in this equation :( x-b-c)\a+[x-c-a]\b+[x-a-c]\c=3?

Answer 1

hey friend !!!! here is your answer

=> (x - b - c)/a + (x - a - b)/c + (x - c - a) / b = 3

=> bc(x - b - c) + ab(x - a - b) + ac(x - c - a) = 3abc

=> bcx - b²c - bc² + abx - a²b - ab² + acx - a²c - ac² = 3abc

=> abx + bcx + cax = 3abc + a²b + ab² + b²c + bc² + a²c + ac²

=> x(ab + bc + ac) = abc + a²b + ab²+ abc + b²c + bc²+ abc + a²c + ac²

=> x(ab + bc + ac) = ab(c + a + b) + bc(a + b + c) + ac(b + a + c)

=> x(ab + bc + ac) = (a + b + c)(ab + bc + ac)

=> x = (a + b + c)(ab + bc + ac)/(ab + bc + ac)

=> x = a + b + c

hope it will help you..

Answer 2

answer is x= a+b+c....wait gor upload image