Question

the value of x so that the point (3,x) lies on the line 2x-3y=0 is​

Answer 1

Question:

The value of x so that the point (3,x) lies on the line 2x-3y=0 is​

Solution:

Given => Point (3,x) lies on the line 2x - 3y = 0 is​

Then, the point (3,x) i.e. x-axis(x) = 3 and y-axis(y) = x

Let's put values

2x - 3y = 0

2(3) - 3(x) = 0

6 - 3x = 0

-3x = -6

x = -6/-3

x = 6/3

x = 2

The point is (3,2) which is on the line 2x - 3y = 0