Question

The vapour pressure of a dilute aqueous solution of glucose is 750mm of mercury at 373k. The mole fraction of solute is​

Answer 1

Pa =P°a . xa

750 = 760. xa

xa=0.9868

xa = 1-xb

Therefore xb=0.0132

Here Pa =VP of solvent on adding solute

P°a = VP of pure solvent

xa= mole fraction of solvent

xb = mole fraction of solute i.e. glucose

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