Question

The velocity of a body changes from 65 m/s - 98 m/s by Time of 12 s . What is distance covered by body if acceleration is 2.75 m/s².

Thnx deepali ✌

Sab off hai tata~​

Answer 1

Answer:

978 m

Explanation:

s = ut + 1/2 at²

= 65 × 12 + 1/2 × 2.75 × 144

= 780 + 198

= 978 m

Alternative Method -

v² - u² = 2as

98² - 65² = 2 × 2.75 × s

( 98 + 65 ) ( 98 - 65 ) = 5.5s

163 × 33 = 5.5s

5379 = 5.5s

5379/5.5 = s

978 m = s