Question

The velocity of a particle having mass 1kg varies with time as v=2t-1.Find work done on the particle in first two seconds

Answer 1

Integrate v

Thus,v=t^2-t

Therefore; v=2

Work done=1/2×m×v^2

=1/2×1×2^2

=2J

I 'm not sure about it but I think its correct

Thank You :)