Question

The velocity of an object changes from 4 m/s to 12 m/s while it covers a distance of
400m. Find the acceleration of the object. How long will it take to cover next 400m

Answer 1

Answer:

Answer:

Explanation:

u=4m/s

v=12m/s

s=400m

2as=v2-u2

800a=144-16

a=122/800m/s2

if s=400 and u=12m/s

s=ut+1/2at2

400=12t+1/2*122/800t2

400=12t+61/800t^2

Answer 2

Answer:

Explanation: initial velocity(u)= 4m/s

Final velocity (v)= 12 m/s

distance (s)= 400 m, acceleration (a)=?

By using kinematical equation,

v^2=u^2+1×a×s

a=v^2-u^2÷s

= 16-144 ÷ 400

a = -0.16 m/s^2