Question

The velocity of an object is given by v = (6t3i + t2j) m/s. Find its acceleration at t = 2s.

Answer 1

V = 6t^3 î + t^2j
To find acceleration we will differentiate this...
Then we will get:
a = 18t^2 î + 2t j
Now putting value of t = 2...
We get...
a = 72 ì + 4j
this is acceleration

Answer 2

Answer:

$\huge\mathcal{\underline{\underline{{A}{\pmb{\sf{nswer \: : - }}}}}}$

V = 6t^3 î + t^2j

To find acceleration we will differentiate this...

• Then we will get:

a = 18t^2 î + 2t j

Now putting value of t = 2...

• We get...

a = 72 ì + 4j (acceleration)