Question

the velocity of body varies with time v=(4t^3+2÷t^2+1) m/s .The displacement of particle from t=1 to t=2 is?​

Answer 1

Answer:

We know that velocity is

dt

dx

=v=4t so dx=4tdt

integrating both sides we get ∫

x

1

x

2

dx=∫

t=2

t=4

4tdt

or displacement =x

2

−x

1

=2t

2

∣

2

4

=2(16−4)=24m