The velocity of particle A is 0.1 m/s and that of particle B is 0.05 m/s .If the mass of particle B is five times that of particle A then the ratio of de Broglie wavelength associated with particle A and B is?
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Answer:
5/2
Explanation:
lamda ,,=1/√2mv
lamda A /lamda B = √2mbvb/√2mava
=(5*0.05)/(1*0.1)
=25/10
=5/2
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