The volume of '1.4ℓ' gas obtained at STP on heating '5.6ℓ' is (molar mass of '1.12 e' '11.2ℓ' O '2NaHCO_(3)longrightarrow^(/_\)Na_(2)CO_(3)+H_(2)O+CO_(2)' O 'NaHCO_(3)=84" "g//mol' O '8.4" "gNaHCO_(3)' 'CO_(2
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Gas stoichiometry is the study of the relative amounts of reactants and products in reactions that involve gases.
EXAMPLE
Calculate the volume of gaseous NO₂ produced by the combustion of 100 g of NH₃ at 0°C and 100 kPa.
Solution
Step 1. Write the balanced chemical equation.
4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(l)
Step 2. Convert mass of NH₃ → moles of NH₃ → moles of NO₂.
100 g NH₃ ×
1
mol NH
3
17.03
g NH
3
×
4
mol NO
2
4
mol NH
3
= 5.872 mol NH₃ (3 significant figures +
1 guard digit)
Step 3. Use the Ideal Gas Law to calculate the volume of NO₂.
P
V
=
n
R
T
V
=
n
R
T
P
=
5.872
mol
×
8.314
kPa⋅L⋅K
−
1
mol
−
1
×
273
K
100
kPa
= 133 L
Explanation:
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