The volume of 12 g of co2 at stp occupy
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7.02 litres . hope you understand please mark brainliest.
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answer is 6.1 L of CO2
because 22.4 L of CO2 are present in 44g of CO2.
so, 44 g - 22.4 L
12 g - ??
= 12 × 22.4 / 44
= 6.109 L
so, there will be 6.109 L of CO2 present in 12 g of CO2
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