Question

the volume of a drop of a rain was found to be 0.448 ml at ntp how many molecules of water and the number of atoms of hydrogen is present in the drop

Answer 1

Taking the density of water to be = 1 g/cm³ or 1g/ml

Mass = Density x Volume

Mass of water = 1 x 0.448 = 0.448g

Molar mass of water, H2O = 2x1 + 16 = 18g/mol

Moles of water = 0.448/18 = 0.0249

Avogadro's number = 6.022 x 10^23

Number of molecules of water = 6.022 x 10^23 x 0.0249

                                                = 1.5 x 10^22


1 molecule of water has 2 hydrogen atoms


Number of hydrogen atoms = 2 x 1.5 x 10^22

                                             = 3 x 10^22

Answer 2

Answer:

Explanation:

Taking the density of water to be = 1 g/cm³ or 1g/ml

Mass = Density x Volume

Mass of water = 1 x 0.448 = 0.448g

Molar mass of water, H2O = 2x1 + 16 = 18g/mol

Moles of water = 0.448/18 = 0.0249

Avogadro's number = 6.022 x 10^23

Number of molecules of water = 6.022 x 10^23 x 0.0249

= 1.5 x 10^22

1 molecule of water has 2 hydrogen atoms

Number of hydrogen atoms = 2 x 1.5 x 10^22

= 3 x 10^22