The volume of a gas at constant pressure of 10^3N/m^2 expands by 0.25m^3. Find the work done by the gas ????
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Answered by
2
Heya.....
Work done :- P ( del ) v =
![10 {}^{3} \times 0.25 = 250j 10 {}^{3} \times 0.25 = 250j](https://tex.z-dn.net/?f=10+%7B%7D%5E%7B3%7D++%5Ctimes+0.25+%3D+250j)
Hope it helps you
![<marquee > prabhudutt <marquee > prabhudutt](https://tex.z-dn.net/?f=+%26lt%3Bmarquee+%26gt%3B+prabhudutt)
Work done :- P ( del ) v =
Hope it helps you
Answered by
1
Work done = p×dv
10^3 × 0.25
=0.25×10^3 joules
;)
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