Psychology, asked by AjitraoXXXXX, 1 year ago

The volume of a gas at constant pressure of 10^3N/m^2 expands by 0.25m^3. Find the work done by the gas ????

Answers

Answered by Anonymous
2
Heya.....


Work done :- P ( del ) v =

10 {}^{3}  \times 0.25 = 250j
Hope it helps you


 <marquee > prabhudutt
Answered by Ashk432
1

Work done = p×dv


10^3 × 0.25


=0.25×10^3 joules


;)

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