The volume of a right circular cone is 9856cm³.If the diameter of the base is 28cm,find.(i)height of the cone (ii)slant height of the cone(iii)curved surface area of the cone.
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i)height=48cm ii)slant height =50cm iii)csa=2198cm
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Given :-
The volume of the right circular cone
= 9856cm^3
Diameter =28 cm
Radius = Diameter/2
Radius of the cone = 14cm
Solution 1 :-
Volume of the cone = 1/3πr^2h
Put the required values in the formula ,
9856 = 1/3 * 22/7 * 14 * 14 * h
h = 9856 * 3 * 7 / 22 * 14 * 14
h = 206976 / 4312
h = 48
Hence , The height of the cone is 48cm
Solution 2 :-
Radius of the cone = 14 cm
Height of the cone = 48cm
Now ,
( l )^2 = (radius)^2 + ( height )^2
Slant height ( l )^2 = √( 14)^2 + ( 48)^2
( l )^2 = 196 + 2304
( l )^2 = 2500
l = 50 cm
Thus , The slant height of a cone is 50 cm
Solution 3 :-
Total surface area of cone
Put the required values in the formula ,
TSA of cone = 22/7 * 14 ( 50 + 14)
TSA of cone = 22 * 2 * 64
TSA of cone = 2816 cm²
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