the volume of circular iron rod of length 1 m is 3850 cm ³ find its radius
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3850= 22/7 × r × r × 100 r2= 3850 × 7/100 × 22 r = 1.75 × 7 r= 3.5cm Therefore diameter = 2 × r Diameter= 2 × 3.5 = 7cm
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Given that the length of the circular rod=1m=100 cm
Volume of the rod= 3850 cm
Volume of the cylinder = πr²h, where r is the radius of the cylinder and h Is the height or length of the cylinder.
πr²h= 3850
22/7×r²×100=3850
r²= 3850×7/22×100
r²= 1225/100
r= √ 1225/100
r= 35/10
r=3.5
radius=3.5 cm
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