Question

The volume of CO2 gas produces when 20 grams of CaCO3 is decomposed

Answer 1

the molecular mass of Ca is 40 C is 12 and O is 16 so by calculating the molecular mass of CaCo3 is 100 and the molecular mass of Co2 is 72
so hundred gram cacl2 produce 72 gram carbon dioxide so 20 grams to produce 14.4 gm carbon dioxide

Answer 2

Answer:

When 20 grams of calcium carbonate CaCO₃ is decomposed, the volume of CO₂ gas produces is equal to 4.48 L.

Explanation:

The decomposition reaction of calcium carbonate (CaCO₃) is given by:

CaCO₃   $\longrightarrow$  CaO (s)  +   CO₂ (g)

The molecular mass  of calcium carbonate = 100g/mol

The molecular mass of carbon dioxide = 44g/mol = 22.4L

From the chemical equation we can say that one mole of CaCO₃ produce one mole of carbon dioxide.

100g of CaCO₃ produces carbon dioxide = 22.4L

20 g of CaCO₃ will produce carbon dioxide $=\frac{20}{100}\times 22.4 = 4.48\;L$

Therefore, the volume 4.48L of carbon dioxide produces, when 20 grams of CaCO3 is decomposed.

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