Question

The volume of water which must be added to the mixture of 350 cm cube of 6 molarity HCland 650 ml of 3 molarity HCl to get a resultant solution of 3 molarity concentration will be

Answer 1

Given:

• The volume of solution one (V1) = 350 mL
• Molarity of solution one (M1) = 6M
• The volume of solution two (V2) = 650 mL
• Molarity of solution two (M2) = 3M
• Resulting molarity (M) = 3M

To find:

The volume of water (V) that needs to be added to the mixture of the two solution such that the resulting molarity is 3M.

Solution:

• The moles in the initial and final solution will be equal.
• Hence, M1V1 + M2V2 = M(V1+V2+V)

                 ⇒6*350 + 3*650 = 3*(350+650+V)

                 ⇒4050 = 3000 + 3V

                 ⇒3V = 1050

                 ⇒V = 450 mL

Answer:

The volume of water (V) that needs to be added to the mixture of the two solution such that the resulting molarity is 3M = 450 mL.