Question

The volume strength of 1.5 NH2O2 solution is

Answer 1

Answer: The volume strength will be 8.4

Explanation:

Volume strength of hydrogen peroxide is defined as the term which is used to express the concentration of $H_2O_2$ in terms of volumes of oxygen gas based on its decomposition to form water and oxygen.

Reaction of decomposition of hydrogen peroxide will be:

$2H_2O_2\rightarrow 2H_2O+O_2$  

Let us assume that the solution of M moles of $H_2O_2$ is present in 1L solution

From the stoichiometry of the reaction:

2 moles of $H_2O_2$ gives 1mol of oxygen

We can also say that 2 moles of $H_2O_2$ produces 22.4 L of oxygen gas at STP.

So, 1mole $H_2O_2$ will produce = $\frac{22.4L}{2}\times 1=11.2L$ of oxygen gas.

Hence, M mole of $H_2O_2$ will produce (11.2 x M) L of Oxygen gas.

We can also say that,

1L of $H_2O_2$ will give (11.2 x M) L of Oxygen gas.

Therefore, the Volume strength of $H_2O_2$ = 11.2 x M

Now, converting this in terms of normality, we get:

n factor for $H_2O_2$ is 2.

We know that:

$N=nM$

So, for $H_2O_2$: $M=\frac{N}{2}$

We are given normality of $H_2O_2$ = 1.5 N

So, Volume strength of $H_2O_2$ = $11.2\times \frac{N}{2}=11.2\times \frac{1.5}{2}=8.4$

Hence,  The volume strength of $H_2O_2$ will be 8.4

Answer 2

Normality (N) = 1.5

Equivalent weight of H2O2 is 17

Strength of H2O2 = Normality x Equivalent weight = 1.5 ×17 = 25.5

2 H202 ------- 2 H2O + O2

(2×34 g) (22.4 L)

Since 68 grams of H2O2 produces 22.4 litres oxygen at NTP,

therefore 25.5 grams of H2O2 will produce = 22.4/68 x 25.5 = 8.4 litre of oxygen

Thus, volume strength of given H2O2 solution is 8.4.