The volume-temperature graphs of a given mass of an ideal
gas at constant pressure are shown below.
What is the correct order of pressures ?
(a) p₁ > p₃ > p₂ (b) p₁ > p₂ > p₃
(c) p₂ > p₃ > p₁ (d) p₂ > p₁ > p₃
Answers
Hence, P 1 > P 2 > P 3
The correct option is (B).
Explanation:
According to the ideal gas equation:
- PV = nRT
At constant number of moles and Temperature T, when Volume is increased, Pressure decreases.
From the graph, we see that at 273 K.
When volume increases, the pressure will decrease from P1 , P 2 , P3.
Hence, P 1 >P 2 >P 3
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The correct order of pressures at given condition are p₁ > p₂ > p₃.
Step by step explanation:
The ideal gas equation is as follows.
P = Pressure of the gas
T = Temperature of the gas
n = Number of moles of the gas
R = Gas constant
V = Volume of the gas.
The volume-temperature graphs are drawn at constant n and T,
when Volume is increased and then pressure is decreases.
In the graph, at 273 K when volume increases, the pressure will decrease from .
Therefore, The correct order of pressures at given condition are p₁ > p₂ > p₃.
Hence, correct option is "b".
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