Question

The weight of 3.2×10^5 atoms of an
element is 8×10^-18g. The atomic wt. of the element should be about

Answer 1

The atomic mass of given element is 15.055g.

Answer 2

Answer:

The atomic weight of the element, W, measured is $15.05g/atom$.

Explanation:

Data given,

The given number of atoms, N = $3.2\times 10^{5}$ atoms

The mass of the element, m = $8\times 10^{-18} g$

The element's atomic weight, W =?

By using the equation given below, we can find out the atomic weight of the element:

• Number of atoms, N = $\frac{Given mass}{Atomic mass} \times N_{A}$

Here, $N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

Therefore,

• $N = \frac{m}{W} \times N_{A}$
• W = $\frac{m}{N}\times N_{A}$

After putting the values of mass, the number of atoms and Avogadro's number in the equation, we get:

• W = $\frac{8\times 10^{-18} }{3.2\times 10^{5} }\times 6.022\times 10^{23}$
• W = $15.05$ g/atom

Hence, the atomic weight of the element, W, measured is $15.05g/atom$.