Question

The weight of a brick is 50 Newton. Its dimensions are 20 cm x10cmx4cm.What

are the maximum and minimum pressure exerted by the brick on the ground?​

Answer 1

GIVEN:

• $\rm{Weight\:of\:Brick= 50N}$

• $\rm{Length\:of\:Brick=20cm}$

• $\rm{Breadth\:of\:Brick = 10cm}$.

• $\rm{Height\:of\:Brick = 4cm}$

TO FIND:-

• The maximum and minimum Pressure exerted by the brick on the Ground.

FORMULAE USED

• ${\boxed{\blue{Area = Length \times{Breadth}}}}$

• ${\boxed{\red{Pressure=\dfrac{Force}{Area}}}}$.

Now,

$\implies\rm{w=mg}$

$\implies\rm{50=m\times{10}}$

$\implies\rm{m=5kg}$

Now,

$\implies\rm{maximum\:Area\:of\:brick=20\times{10}}$

$\implies\rm{Maximum\:Area= 200cm=0.02m^2}$

Now, Using the Formulae.

$\implies\rm{P=\dfrac{Force}{Area}}$

$\implies\rm{Maximum\:Pressure=\dfrac{\cancel{50}}{\cancel{0.02}}}$

$\implies\rm{P=2500Nm^-2}$.

Now,

$\implies\rm{minimum\:Area\:of\:brick=10\times{4}}$

$\implies\rm{Maximum\:Area= 40cm=0.040m^2}$

Now, Using the Formulae.

$\implies\rm{P=\dfrac{Force}{Area}}$

$\implies\rm{Maximum\:Pressure=\dfrac{\cancel{50}}{\cancel{0.040}}}$

$\implies\rm{P=1250Nm^-2}$.

Hence, The Maximum force and minimum force exerted by brick on the ground is 2500Nm² and 1250Nm² Respectively.